(3x^3-6x)(x+1)=0

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Solution for (3x^3-6x)(x+1)=0 equation: 


Simplifying
(3x3 + -6x)(x + 1) = 0

Reorder the terms:
(-6x + 3x3)(x + 1) = 0

Reorder the terms:
(-6x + 3x3)(1 + x) = 0

Multiply (-6x + 3x3) * (1 + x)
(-6x * (1 + x) + 3x3 * (1 + x)) = 0
((1 * -6x + x * -6x) + 3x3 * (1 + x)) = 0
((-6x + -6x2) + 3x3 * (1 + x)) = 0
(-6x + -6x2 + (1 * 3x3 + x * 3x3)) = 0
(-6x + -6x2 + (3x3 + 3x4)) = 0
(-6x + -6x2 + 3x3 + 3x4) = 0

Solving
-6x + -6x2 + 3x3 + 3x4 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '3x'.
3x(-2 + -2x + x2 + x3) = 0

Ignore the factor 3.

Subproblem 1
Set the factor 'x' equal to zero and attempt to solve:

Simplifying
x = 0

Solving
x = 0

Move all terms containing x to the left, all other terms to the right.

Simplifying
x = 0

Subproblem 2
Set the factor '(-2 + -2x + x2 + x3)' equal to zero and attempt to solve:

Simplifying
-2 + -2x + x2 + x3 = 0

Solving
-2 + -2x + x2 + x3 = 0

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.
Solution
x = {0}

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